The A’s choking down the stretch would be a welcome plot twist.Oakland lost to the Angel's. 1 game back of the A's now
As I understand, the teams with the worst head to head records of the 3 play in the Monday game. We have the worst head to head record of the 3 so we'd play on Monday.So, if I am understanding correctly, if all 3 teams end with the same record:
Mon 9/30- Tampa Bay (Team B) @ Oakland (Team A)- Winner hosts the Wild Card Game on Weds 10/2
Tues 10/1- Loser Above @ Cleveland (Team C)- Winner becomes Road team for Wild Card Game on 10/2
Weds 10/2- Wild Card Game
Fri 10/4- ALDS Game 1
Edit- To further explain:
Each team "drafts" which position they want, based off of H2H record among themselves. Oakland is 1, Tampa is 2, Cleveland is 3
Oakland would surely choose Team A because you have 2 shots to get into the Wild Card Game and you host the first game
I would think Tampa chooses Team B simply because they get 2 shots to get into the Wild Card Game. Maaaybe they choose Team C to avoid what would be absolute travel hell (Toronto>Oakland>Cleveland>Oakland>Houston/New York) in a 5 day span, but I think the 2 shots to get in makes that worth it.
As I understand, the teams with the worst head to head records of the 3 play in the Monday game. We have the worst head to head record of the 3 so we'd play on Monday.
What that means is the As can choose to be team A,B or C, not that we are automatically team C.This is what I am basing it off of:
If the three teams were to wind up tied, they would draft positions for the following scenario: Club A hosts Club B, with the winner of that game becoming the host team for the Wild Card game, and the loser traveling to Club C to determine the road team for the actual Wild Card game. According to MLB’s tiebreaker scenario playbook, the pecking order for that draft would be based upon combined winning percentage against the other two teams, which means it’s the A’s (.692, 9-4), Rays (.642, 9-5), and Indians (.154, 2-11) in that order.
Team Entropy 2019: Is This Thing Even On?
As the season nears its conclusion, an update on the potential for chaos.blogs.fangraphs.com
and
Three-Club Tie for Two Wild Card Spots:
After Clubs have been assigned their A, B and C designations, Club A would host Club B. The winner of the game would be declared one Wild Card winner. Club C would then host the loser of the game between Club A and Club B to determine the second Wild Card Club.
How to determine playoff tiebreakers
With the 2022 expansion of the postseason field from 10 teams to 12 teams, tiebreaker games will no longer be used to resolve ties in the standings at the conclusion of the regular season. That means no more “Game 163.” • 2022 bracket and tiebreaker scenarios, explained Instead, ties willwww.mlb.com
What that means is the As can choose to be team A,B or C, not that we are automatically team C.
It’s a dumb way to explain it, but that’s because MLB is still clouded by Bud Seligs incompetence.
Wow, I misread it. I assumed A and B played each other, then the winner played C, and then the winner of that game went onto the ALDS.Correct, but I'd say it is extremely likely that the Indians will be Team C since A & B are guaranteed 2 shots at it.
A's and Ray's should be pretty pissed they're subjected to these tie breakers when they both smoked the Indians this year. I'll take it though.