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Scoreboard Watching

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Oh, and the Rays have Morton taking the mound tomorrow. We may have to win out just to play a Game 163. This is nuts.
 
By the way, the Nationals clinched a playoff spot last night with their win over the Phillies and the Cubs loss to the Pirates (lol). Means the Indians will avoid Scherzer this weekend.
 
3 walk off wins and 1 win in the 10th in the Rays last 6 games, unbelievable

At least Oakland has stumbled and the Indians are only 1 game back from them.
 
Oakland has played out of their minds for the past 6-8 weeks. They’re due for a reality check and it may be here just in the Knick of time.
How awesome would it be for them to lose a couple more and open the door for the Tribe?
The Rays are just freakin lucky (and good). Need the Yankees to give them a loss today.
 
So, if I am understanding correctly, if all 3 teams end with the same record:

Mon 9/30- Tampa Bay (Team B) @ Oakland (Team A)- Winner hosts the Wild Card Game on Weds 10/2

Tues 10/1- Loser Above @ Cleveland (Team C)- Winner becomes Road team for Wild Card Game on 10/2

Weds 10/2- Wild Card Game

Fri 10/4- ALDS Game 1


Edit- To further explain:

Each team "drafts" which position they want, based off of H2H record among themselves. Oakland is 1, Tampa is 2, Cleveland is 3

Oakland would surely choose Team A because you have 2 shots to get into the Wild Card Game and you host the first game

I would think Tampa chooses Team B simply because they get 2 shots to get into the Wild Card Game. Maaaybe they choose Team C to avoid what would be absolute travel hell (Toronto>Oakland>Cleveland>Oakland>Houston/New York) in a 5 day span, but I think the 2 shots to get in makes that worth it.
 
Last edited:
So, if I am understanding correctly, if all 3 teams end with the same record:

Mon 9/30- Tampa Bay (Team B) @ Oakland (Team A)- Winner hosts the Wild Card Game on Weds 10/2

Tues 10/1- Loser Above @ Cleveland (Team C)- Winner becomes Road team for Wild Card Game on 10/2

Weds 10/2- Wild Card Game

Fri 10/4- ALDS Game 1


Edit- To further explain:

Each team "drafts" which position they want, based off of H2H record among themselves. Oakland is 1, Tampa is 2, Cleveland is 3

Oakland would surely choose Team A because you have 2 shots to get into the Wild Card Game and you host the first game

I would think Tampa chooses Team B simply because they get 2 shots to get into the Wild Card Game. Maaaybe they choose Team C to avoid what would be absolute travel hell (Toronto>Oakland>Cleveland>Oakland>Houston/New York) in a 5 day span, but I think the 2 shots to get in makes that worth it.
As I understand, the teams with the worst head to head records of the 3 play in the Monday game. We have the worst head to head record of the 3 so we'd play on Monday.
 
As I understand, the teams with the worst head to head records of the 3 play in the Monday game. We have the worst head to head record of the 3 so we'd play on Monday.

This is what I am basing it off of:


If the three teams were to wind up tied, they would draft positions for the following scenario: Club A hosts Club B, with the winner of that game becoming the host team for the Wild Card game, and the loser traveling to Club C to determine the road team for the actual Wild Card game. According to MLB’s tiebreaker scenario playbook, the pecking order for that draft would be based upon combined winning percentage against the other two teams, which means it’s the A’s (.692, 9-4), Rays (.642, 9-5), and Indians (.154, 2-11) in that order.


and


Three-Club Tie for Two Wild Card Spots:
After Clubs have been assigned their A, B and C designations, Club A would host Club B. The winner of the game would be declared one Wild Card winner. Club C would then host the loser of the game between Club A and Club B to determine the second Wild Card Club.


 
This is what I am basing it off of:


If the three teams were to wind up tied, they would draft positions for the following scenario: Club A hosts Club B, with the winner of that game becoming the host team for the Wild Card game, and the loser traveling to Club C to determine the road team for the actual Wild Card game. According to MLB’s tiebreaker scenario playbook, the pecking order for that draft would be based upon combined winning percentage against the other two teams, which means it’s the A’s (.692, 9-4), Rays (.642, 9-5), and Indians (.154, 2-11) in that order.


and


Three-Club Tie for Two Wild Card Spots:
After Clubs have been assigned their A, B and C designations, Club A would host Club B. The winner of the game would be declared one Wild Card winner. Club C would then host the loser of the game between Club A and Club B to determine the second Wild Card Club.


What that means is the As can choose to be team A,B or C, not that we are automatically team C.

It’s a dumb way to explain it, but that’s because MLB is still clouded by Bud Seligs incompetence.
 
What that means is the As can choose to be team A,B or C, not that we are automatically team C.

It’s a dumb way to explain it, but that’s because MLB is still clouded by Bud Seligs incompetence.

Correct, but I'd say it is extremely likely that the Indians will be Team C since A & B are guaranteed 2 shots at it.

A's and Ray's should be pretty pissed they're subjected to these tie breakers when they both smoked the Indians this year. I'll take it though.
 
Correct, but I'd say it is extremely likely that the Indians will be Team C since A & B are guaranteed 2 shots at it.

A's and Ray's should be pretty pissed they're subjected to these tie breakers when they both smoked the Indians this year. I'll take it though.
Wow, I misread it. I assumed A and B played each other, then the winner played C, and then the winner of that game went onto the ALDS.
 

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